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SBI PO Prelims Full Mock Test 100 Questions 100 Marks 60 Mins It is given that principal = Rs. 30000 Rate = 7% Let time period = n Compound Interest = Rs. 4347 Amount = Principal + Compound interest = Rs. 34347 We know, Amount = Principal (1 + Rate/100)n ⇒ 34347 = 30000 (1 + 7/100)n ⇒ 11449/10000 = (107/100)n ⇒ (107/100)2 = (107/100)t Time period = 2 years Last updated on Sep 21, 2022 The State Bank of India (SBI) has released the official notification of the SBI PO 2022 Recruitment. A total of 1673 vacancies have been released under SBI PO 2022-23 Recruitment. The SBI has revised the mains exam pattern a bit. The candidates can check out the SBI PO Mains Exam Pattern here. The SBI PO Eligibility includes graduation degree, so the candidates who fulfill eligibility will be able to apply from 22nd September 2022 to 12th October 2022. The selection process has 3 phases. Candidates who will be selected will get a salary range between Rs. 36000 - Rs. 63840. Let's discuss the concepts related to Interest and Compound Interest. Explore more from Quantitative Aptitude here. Learn now! A. 2 B. $$2\frac{1}{2}$$ C. 3 D. 4 Solution(By Examveda Team)$$\eqalign{ & {\text{Amount}} = Rs.\,\left( {30000 + 4347} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,34347 \cr & {\text{Let}}\,{\text{the}}\,{\text{time}}\,{\text{be}}\,n\,{\text{years}} \cr & {\text{Then}},30000\,{\left( {1 + \frac{7}{{100}}} \right)^n} = 34347 \cr & \Rightarrow {\left( {\frac{{107}}{{100}}} \right)^n} = \frac{{34347}}{{30000}} = \frac{{11449}}{{10000}} = {\left( {\frac{{107}}{{100}}} \right)^2} \cr & \therefore n = 2\,{\text{years}} \cr} $$ The compound interest on Rs. 30000 at 7 % per annum is Rs. 4347 . The period in years is: Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Solution The correct option is A 2P = Rs. 30000, r =7% p.a., C.I = Rs. 4347 ⇒ Amount = Rs. 30000+Rs. 4347 = Rs. 34347 ∴34347=30000(1+7100)n ⇒(107100)n=3434730000=1144910000 ⇒(107100)n=⇒(107100)2⇒n=2No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Solution The correct option is D2Let the period be n years. Then, amount after n years = Rs.(30000 + 4347) = Rs. 34347⇒P(1+R100)n=34347⇒30000(1+7100)n=34347⇒30000(107100)n=34347⇒(107100)n=3434730000= 1144910000= (107100)2 (adsbygoogle = window.adsbygoogle || []).push({}); ⇒n=2 yearsTextbooks Question Papers Home What is the compound interest on 30000 at 7?30,000 at 7% per annum is Rs. 4347.
What will be the compound interest on Rs 30000?The compound interest on Rs. 30000 at 7% per annum is Rs. 4347.
What is the compound interest on rupees 20000 at 10% for 2 years?Where P is principal, R is rate of interest and T is time. ∴ The compound interest for 2 years is Rs. 2464.
What will be the compound interest on a sum of rupees 25000 after 3 years at the rate of 12 PCPA?(1+12100)3=25000(2825×2825×2825)=35123.20. Q. What will be the compound interest on a sum of Rs. 25,000 after 3 years at the rate of 12 p.c.p.a.?
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