What is the compounded amount if the principal of rupees 30000 and interest earned at 7% per annum is rupees 4347?

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It is given that principal = Rs. 30000

Rate = 7%

Let time period = n

Compound Interest = Rs. 4347

Amount = Principal + Compound interest = Rs. 34347

We know, Amount = Principal (1 + Rate/100)n

⇒ 34347 = 30000 (1 + 7/100)n

⇒ 11449/10000 = (107/100)n

⇒ (107/100)2 = (107/100)t

Time period = 2 years

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A. 2

B. $$2\frac{1}{2}$$

C. 3

D. 4

Solution(By Examveda Team)

$$\eqalign{ & {\text{Amount}} = Rs.\,\left( {30000 + 4347} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,34347 \cr & {\text{Let}}\,{\text{the}}\,{\text{time}}\,{\text{be}}\,n\,{\text{years}} \cr & {\text{Then}},30000\,{\left( {1 + \frac{7}{{100}}} \right)^n} = 34347 \cr & \Rightarrow {\left( {\frac{{107}}{{100}}} \right)^n} = \frac{{34347}}{{30000}} = \frac{{11449}}{{10000}} = {\left( {\frac{{107}}{{100}}} \right)^2} \cr & \therefore n = 2\,{\text{years}} \cr} $$

The compound interest on Rs. 30000 at 7 % per annum is Rs. 4347 . The period in years is:

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Solution

The correct option is A 2P = Rs. 30000, r =7% p.a., C.I = Rs. 4347 ⇒ Amount = Rs. 30000+Rs. 4347 = Rs. 34347 ∴34347=30000(1+7100)n ⇒(107100)n=3434730000=1144910000 ⇒(107100)n=⇒(107100)2⇒n=2

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Solution

The correct option is D2Let the period be n years. Then, amount after n years = Rs.(30000 + 4347) = Rs. 34347⇒P(1+R100)n=34347⇒30000(1+7100)n=34347⇒30000(107100)n=34347⇒(107100)n=3434730000= 1144910000= (107100)2 (adsbygoogle = window.adsbygoogle || []).push({}); ⇒n=2 years

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