What will be the compound interest on a sum of rupees 25000 after 2 years at the rate of 12% compounded annually?

P = Rs 25000, n = 3 years, r = 12% p.a

\(\therefore\) Amount = P\(\Big(1+\frac{r}{100}\Big)^n\) = Rs 25000 x\(\Big(1+\frac{12}{100}\Big)^3\)

= Rs 25000 x \(\Big(\frac{112}{100}\Big)^3\) = Rs 25000 x \(\frac{28}{25}\times\frac{28}{25}\times\frac{28}{25}\)

= RS 35123.20

\(\therefore\) Compound interest = Rs (35123.20 – 25000) = Rs 10123.20

A. Rs. 9000.30

B. Rs. 9720

C. Rs. 10123.20

D. Rs. 10483.20

E. None of these

Solution(By Examveda Team)

$$\eqalign{ & {\text{Amount}} = Rs.\,\left[ {25000 \times {{\left( {1 + \frac{{12}}{{100}}} \right)}^3}} \right] \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,\left( {25000 \times \frac{{28}}{{25}} \times \frac{{28}}{{25}} \times \frac{{28}}{{25}}} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,35123.20 \cr & \therefore {\text{C}}{\text{.I}}{\text{.}} = Rs.\left( {35123.20 - 25000} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,10123.20 \cr} $$

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What will be the compound interest on 25000 after 3 years at 12% per annum?

(1+12100)3=25000(2825×2825×2825)=35123.20. Q.

What is the compound interest on Rs 25000 for 2 years?

UPLOAD PHOTO AND GET THE ANSWER NOW! Solution : Amount`=P(1+r/100)^t`<br> Amount`=25000(1+4/100)^1`<br> After 2 years <br> Amount`=25000(1+4/100)(1+5/100)`<br> `A=27300`<br> option c is correct.

How much will ₹ 25000 amount to in 2 years at compound interest if the rates are 4% pa and 5% pa for the two successive years?

Here P = Rs. 25000, t = 2 years, r = 4%, 5% successively. Hence, Amount = Rs. 27300.

What would be the compound interest on a principal of Rs 10000 interest rate 12% for 3 years assuming interest is compounded every month?

1,664. ∴ The compound interest is Rs. 1,664.