The sum which will amount to ₹ 8748 in 2 years at 8 per annum compound interest is

Solution

let use this formula to find the rate of interest that is

Amount=principal (1+$$\frac{r}{100})^t$$

Given data in the question is 

Amount=8748

Principal=7500

Time=2years

Substitute above values in the formula then we will get

8748=7500(1+$$\frac{r}{100})^2$$

$$\frac{8748}{7500}$$=(1+$$\frac{r}{100})^2$$

Divide 8748 and 7500 by 12 then we get

$$\frac{729}{625}$$=(1+$$\frac{r}{100})^2$$

By eliminating square we get

$$\frac{27}{25}$$=(1+$$\frac{r}{100})$$

$$\frac{r}{100}$$=$$\frac{27}{25}$$-1

$$\frac{r}{100}$$=$$\frac{2}{25}$$

Rate of interest=$$\frac{100}{25}×2$$

Rate of interest=8

Therefore rate of compound interest=8%p.a

Now we have to find the simple interest for the sum ₹7500 for $$\frac{23}{5}$$ years at the rate=2×rate of interest

Rate of interest=2×8=16

Using the simple interest formula

Simple interest=$$\frac{principal×rate of interest ×time}{100}$$

Simple interest=$$\frac{7500×16×23}{5×100}$$

Simple interest=5520₹

Correct Answer - Option 2 : Rs. 3300

Given:

Principal = Rs. 7500

Amount = Rs. 8748

Time = 2 years

Concept used:

A = P × (1 + r/100)t

S.I = (P × R × T)/100

where A = amount, P = principal, R = rate of interest and t = time

Calculation:

7500 × (1 + r/100)2 = 8748

⇒ (1 + r/100)2 = 8748/7500 = 2916/2500

⇒ (1 + r/100)2 = (54/50)2

⇒ 1 + r/100 = 54/50

⇒ r/100 = (54/50) - 1 = 4/50

⇒ r = 8%

now,

according to the question,

P = Rs. 7500, r = 8 × 2.5 = 20% and time = 11/5 years

S.I = (7500 × 20 × 11/5)/100

⇒ (7500 × 4 × 11)/100 = 75 × 4 × 11

⇒ 300 × 11 = 3300

∴ The interest is Rs. 3300.

Correct Answer - Option 2 : 8%

Given:

Amount = Rs 8748

Principal = Rs 7500

Time  = 2 years

Formula:

A = P(1 + R/100)n

Calculation:

A = P(1 + R/100)n

⇒ 8748 = 7500(1 + R/100)2

⇒ (1 + R/100)2 = 8748/7500

⇒ (1 + R/100)2 = 729/625

⇒ 1+ R/100 = 27/25

⇒ R/100 = 27/25 – 1

⇒ R/100 = 2/25

⇒ R = (2/25) × 100

⇒ R = 8%

∴ Rate of compound interest per annum is 8%

A sum of Rs. 7,500 amounts to Rs. 8,748 after 2 years at a certain rate per cent per annum compounded annually. What will be the simple interest for 3 years at double the earlier rate of interest?

This question was previously asked in

SSC MTS 2020 (Held On : 7 Oct 2021 Shift 2 ) Official Paper 8

View all SSC MTS Papers >

  1. 3,600
  2. 3,750
  3. 4,200
  4. 2,800

Answer (Detailed Solution Below)

Option 1 : 3,600

Free

CT : GK (Ancient History)

10 Questions 10 Marks 6 Mins

Given

Principal  = Rs.7500

Amount = Rs 8748

Time = 2 years

Formula used

A = P(1 + r%)t

Simple interest = prt/100

Interest = Amount - Principal

where A, p, r, t are Amount, principal, rate and time respectively

Calculation

8748 = 7500(1 + r%)2

⇒ 8748/7500 = (1 + r/100)2

⇒ 8748/7500 = (100 + r)2/(100)2

⇒ (8748 × 100 × 100)/7500 = (100 + r)2

⇒ 11664 = (100 + r)2

⇒ √ 11664 = 100 + r

⇒ 108 = 100 + r

⇒ 108 - 100 = r

⇒ 8 = r

rate is double = 2(8)

16

Simple interest = (7500 × 16 × 3)/100

⇒ 3600

∴ The simple interest on Rs.7500 for 3 years at double the earlier rate is Rs.3600.

Last updated on Oct 27, 2022

The SSC MTS Tier II Admit Card has been released. The paper II will be held on 6th November 2022. Earlier, the result for the Tier I was released. The candidates who are qualified in the SSC MTS Paper I are eligible for the Paper II. A total of 7709 vacancies are released, out of which 3854 vacancies are for MTS Group age 18-25 years, 252 vacancies are for MTS Group age 18-27 years and 3603 vacancies are for Havaldar in CBIC. 

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